
X_n)是来自总体N(mu,sigma^2)的样本,overline(X)为样本均值,S^2为样本方差,则(overline(X)-mu)/(S/sqrt(n)
(B) (n-1)(S)^2+(overline {X)}^2 (C) (S)^2+(overline {X)}^2. (D) dfrac (n-1)(n)(S
A)(S^2)/(sigma^2) sim chi^2(n-1) B)(n(overline(X)-mu)^2)/(S^2) sim F(1, n-1)
(overline (X))=dfrac ({sigma )^2}(n)-|||-C. (overline (X)-mu )=dfrac ({sigma )^2
(sigma )_(n)=sqrt (dfrac {pi (1-pi ))(n)}-|||-C. (sigma )_(overline {x)}=dfrac (
dfrac (1)(n-1)sum _(i=1)^n(({X)_(i)-overline (X))}^2 .-|||-n-|||-C. sqrt (dfrac
(D) (overline (x)-(u)_(a12)dfrac (2)(sqrt {n)},overline (x)+(u)_(a12)dfrac (2)(s
设X_(1),X_(2),...,X_(n)是来自总体N(mu,sigma^2)的样本,overline(X),S^2分别为样本均值和方差,则(overline
,(X)_(n+1))(ngt 1) 取自总体 sim N(mu ,(sigma )^2) . overline (X)=dfrac (1)(n)sum _(i
,(X)_(n+1))(ngt 1) 取自总体 sim N(mu ,(sigma )^2) , overline (X)=dfrac (1)(n)sum _(i