26.在600K,100 kPa压力下,生石膏的脱水反应为-|||-(O)_(4)cdot 2(H)_(2)O(s)arrow CaS(O)_(4)(s)+2(H)_(2)O(g)-|||-试计算:该反应进度为1mol时的Q,W, Delta (U)_(m) Delta (H)_(m) Delta (S)_(m) Delta (A)_(m) 及 Delta Gm 。已知各物-|||-质在298K,100 kPa的热力学数据为-|||-物质 (Delta )_(1)(H)_(m)^theta /(kJcdot (mol)^-1) ({S)_(m)}^theta /(1cdot (mol)^-1cdot (K)^-1) _(Pm)/(Jcdot (mol)^-1cdot (K)^-1)-|||-CaSO4·2H2O(s) -2021.12 193.97 186.20-|||-CaSO4(s) -1432.68 106.70 99.60-|||-H2O(g) -241.82 188.83 33.58

26.在600K,100 kPa压力下,生石膏的脱水反应为-|||-(O)_(4)cdot 2(H)_(2)O(s)arrow CaS(O)_(4)(s)+2(

在 600 K、100 kPa 压力下，生石膏的脱水反应为(CaS)({{O)}_4}cdot 2({{H)}_2}(O)({( {s) )}=}(CaS)({

在 600 K、100 kPa 压力下，生石膏的脱水反应为CaSO4⋅2H2O(s)=CaSO4(s)+2H2O(g)试计算该反应进度为 1 mol 时的 Q、

4-13 273K时,反应-|||-(Cl)_(2)cdot 6(H)_(2)O(s)leftharpoons (S)_(r)(Cl)_(2)cdot 2(H)

4.9某化合物A的水合晶体A·3H2 O脱水反应过程为-|||-cdot 3(H)_(2)O(s)=!=!= Acdot 2(H)_(2)O(s)+(H)_(2

2-2 利用附录Ⅲ的数据,计算下列反应的 Delta (H)_(m)-|||-(1) _(3)(O)_(4)(s)+4(H)_(2)(g)arrow 3Fe(s

例3 298K和p^θ压力下,有化学反应:-|||-_(2)S(O)_(4)(s)+(H)_(2)((O)^6)=2Ag(s)+(H)_(2)S(O)_(4)(

已知298 K时反应：3 ( Fe(s)) + 4 ( H)_2(O(g)) = (Fe)_3(O)_4((s)) + 4 ( H)_2((g))Delta_(

已知 (298 K) 时 φ⊖Ag+| Ag=0.799 V，电池 (Pt)|({{H)}_2}|({{H)}_2}(S)({{O)}_4}((aq))|(A)

(2) _(2)(O)_(2)+(I)^-+(H)^+ →-|||-(4) FeCl3+H2S- →-|||-(6) +HN(O)_(3) (浓)→-|||-(