设
, 求
和
设(x)=dfrac (1-x)(1+x), 则(x)=dfrac (1-x)(1+x)设,则
求极限lim _(xarrow 0)dfrac (x)(sqrt {1-x)-1}= ()lim _(xarrow 0)dfrac (x)(sqrt {1-x)
设=ln sqrt (dfrac {1-x)(1-{x)^2}}则 dy|=ln sqrt (dfrac {1-x)(1-{x)^2}}设则dy|
=dfrac (sqrt {1+x)-sqrt (1-x)}(sqrt {1+x)+sqrt (1-x)}
int dfrac (1)({x)^2}sqrt (dfrac {1-x)(1+x)}dx
(9) =dfrac (sqrt {1+x)-sqrt (1-x)}(sqrt {1+x)+sqrt (1-x)} ;
求极限:lim _(xarrow 1)(dfrac (1)(1-x)-dfrac (3)(1-{x)^3})-|||-__ __.求极限:.
(1) lim _(xarrow 0)((1-x))^dfrac (1{x)}; ()
不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (
lim _(xarrow 1)(dfrac (1)(1-x)-dfrac (3)(1-{x)^3})-|||-__ __;;