=dfrac (sqrt {1+x)-sqrt (1-x)}(sqrt {1+x)+sqrt (1-x)}
lim _(xarrow 0)dfrac (sqrt {1+x)+sqrt (1-x)-2}(sqrt {1+{x)^2}-1}
int dfrac (1)({x)^2}sqrt (dfrac {1-x)(1+x)}dx
函数=x+sqrt (1-x)的极值为( )=x+sqrt (1-x)=x+sqrt (1-x)=x+sqrt (1-x)=x+sqrt (1-
A.sqrt(1+x) B.(sqrt(1+x))/(2) C.(sqrt(1+x))/(sqrt(x)) D.(sqrt(1+x))/(2sqrt(x)
求下列函数的n阶导数:-|||-(1) =sqrt [m](1+x) ;-|||-(2) =dfrac (1-x)(1+x)
(7) lim _(xarrow infty )dfrac (sqrt {1+x)-1}(sqrt [3]{1+x)-1}
求极限lim _(xarrow 0)dfrac (x)(sqrt {1-x)-1}= ()lim _(xarrow 0)dfrac (x)(sqrt {1-x)
设=ln sqrt (dfrac {1-x)(1-{x)^2}}则 dy|=ln sqrt (dfrac {1-x)(1-{x)^2}}设则dy|
不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (