函数=x+sqrt (1-x)的极值为（ ）=x+sqrt (1-x)=x+sqrt (1-x)=x+sqrt (1-x)=x+sqrt (1-x)

求函数=x+sqrt (1-x)在=x+sqrt (1-x)上的最大值.求函数在上的最大值.

[题目]求函数 =x+sqrt (1-x) 的极值.

=dfrac (sqrt {1+x)-sqrt (1-x)}(sqrt {1+x)+sqrt (1-x)}

(9) =dfrac (sqrt {1+x)-sqrt (1-x)}(sqrt {1+x)+sqrt (1-x)} ;

15.函数y=x+sqrt(1-x)在闭区间[-5,1]上的最小值为____.15.函数$y=x+\sqrt{1-x}$在闭区间[-5,1]上的最小值为____

(1) =ln (x+sqrt ({x)^2+1})

求极限lim _(xarrow 0)dfrac (x)(sqrt {1-x)-1}= ()lim _(xarrow 0)dfrac (x)(sqrt {1-x)

求lim _(xarrow infty )dfrac (ln (x+sqrt {{x)^2+1)}-ln (x+sqrt ({x)^2-1})}({({e)^d

(2) (x)=ln (x+sqrt (1+{x)^2});

(11) =ln (x+sqrt (1+{x)^2}) ;