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判断题:tan x)=(sec )^2xtan x)=(sec )^2x 正确 tan x)=(sec )^2x 错误判断题:正确错误
已知 =sqrt (xsqrt {x)}+xtan x-(e)^2, 求y`.
sec^2xtan ydx+sec^2ytan xdy=0$sec^{2}x\tan ydx+sec^{2}y\tan xdy=0$
lim _(xarrow 0)(dfrac (1)(xtan x)-dfrac (1)({x)^2});
lim _(xarrow 0)dfrac (xtan x)(sqrt {1-{x)^2}-1}=________.________.
(8) lim _(xarrow 0)dfrac (xtan x)(sqrt {1-{x)^2}-1}
[题目]-|||-lim _(xarrow 0)dfrac (xtan x)(sqrt {1-{x)^2}-1}
微分方程 (e)^xtan ydx+(1-(e)^x)(sec )^2ydy=0 的通解是 __
设=(x)^2(e)^x,则=(x)^2(e)^x=( )。A =(x)^2(e)^xB =(x)^2(e)^xC =(x)^2(e)^xD
计算极限__-|||-lim _(xarrow 0)dfrac ({(1+{x)^2)}^dfrac (1{3)}-1}(xtan x)=计算极限