判断题：tan x)'=(sec )^2xtan x)'=(sec )^2x 正确 tan x)'=(sec )^2x 错误

(tan x)^prime=1/(cos x)^2=(sec x)^2=( )题型说明：共15题，每题2分。26. (2.0分) $(\tan x)^{\pri

[题目]如果 f(x)= () ,那么 (x)=0-|||-A、 arcsin 2x+axccos x-|||-B、 (sec )^2+(tan )^2x-||

(ln sec x+tan x)=______.______.

4.设 =(tan )^3(2x), 则 = ()-|||-A.6sec^22x-|||-B.6tan^22xsec^22x-|||-C.3sin^22x co

题型说明:共15题,每题2分。36.(tan x)^prime=1/(cos x)^2=(sec x)^2=( )题型说明:共15题,每题2分。36.(2.0分

(x)=(e)^2xtan x(x)=(e)^2xtan x(x)=(e)^2xtan x(x)=(e)^2xtan x设,则.

对于函数 f(x, y) 若 f(x, 2x)= x^2 + 3x, f_x(x, 2x)= 6x + 1, 则 f_y(x, 2x)= ().A. $x +

(5)求方程 (sec )^2y+dfrac (x)(1+{x)^2}tan y=x 满足条件 (|)_(x=0)=0 的特解.-|||-求解下列一阶微分方程

5.求极限 lim _(xarrow 0)dfrac ({tan )^2x-(x)^2}({x)^2(tan )^2x}

sec^2xtan ydx+sec^2ytan xdy=0$sec^{2}x\tan ydx+sec^{2}y\tan xdy=0$