(ln sec x+tan x)=______.

判断题：tan x)=(sec )^2xtan x)=(sec )^2x 正确 tan x)=(sec )^2x 错误判断题：正确错误

(tan x)^prime=1/(cos x)^2=(sec x)^2=( )题型说明：共15题，每题2分。26. (2.0分) $(\tan x)^{\pri

21.计算极限 lim _(xarrow {0)^+}dfrac (ln tan 5x)(ln tan 2x)

(2) =ln tan dfrac (x)(2);

int dfrac (ln tan x)(cos xsin x)dx

[题目]-|||-证明:当 lt xlt dfrac (pi )(2) 时, sin x+tan xgt 2x

11 lim_(xto0)(ln(1+x+x^2)+ln(1-x+x^2))/(sec x-cos x)=_.11 $\lim_{x\to0}\frac{\ln

【11】lim_(xto0)(ln(1+x+x^2)+ln(1-x+x^2))/(sec x-cos x)=【11】$\lim_{x\to0}\frac{\ln

lim _(xarrow 0)dfrac (ln (1+{x)^2)}(sec x-cos x)..

10) lim _(xarrow 0)dfrac (ln (1+{x)^2)}(sec x-cos x)