[题目]如果 f(x)= () ,那么 '(x)=0-|||-A、 arcsin 2x+axccos x-|||-B、 (sec )^2+(tan )^2x-|||-C、 (sin )^2x+(cos )^2(1-x)-|||-D、 arctan x+arctan x

判断题：tan x)=(sec )^2xtan x)=(sec )^2x 正确 tan x)=(sec )^2x 错误判断题：正确错误

[题目] (sin )^2x+(cos )^2x= __

lim _(xarrow 0)dfrac (ln ({sin )^2x+(e)^x)-x}(ln ({x)^2+(e)^2x)-2x}

6.求下列极限:-|||-lim _(xarrow 0)dfrac (ln ({sin )^2x+(e)^x)-x}(ln ({e)^2x-(x)^2)-2x}

[单选题]已知f’（x）=sec2x+sin2x，且f（0）=3/2，则f（x）等于（）．A . B . C . D .

证明:函数-|||-f(x,y)= ((x)^2+(y)^2)sin dfrac (1)(sqrt {{x)^2+(y)^2}}, ^2+(y)^2neq 0,

5.求极限 lim _(xarrow 0)dfrac ({tan )^2x-(x)^2}({x)^2(tan )^2x}

函数f（x）=x-2sin(x)/(2)cos(x)/(2)，则f（0）=（ ）A. 0B. 1C. -1D. $\sqrt{2}$

[题目]已知 (x)=(x)^2+(int )_(0)^2f(x)dx, 则∫f-|||-(x) = __ .

f(x)=sin x，则f(-arcsin(1)/(2))=（）A. 2B. 1C. $\frac{1}{2}$D. $-\frac{1}{2}$