[题目]已知 (x)=(x)^2+(int )_(0)^2f(x)dx, 则∫f-|||-(x) = __ .

[题目]设连续函数f(x)满足 (x)=(x)^2-(int )_(0)^2f(x)dx ,则-|||-(int )_(0)^2f(x)dx=

3.已知 (int )_(0)^2f(x)dx=3 ,则 (int )_(0)^2[ f(x)+6] dx= __ 一

已知 (x)cdot (int )_(0)^2f(x)dx=8, 且 (0)=0, (x)geqslant 0, 则 f(x)= __

设 f(2)=4 , (int )_(0)^2f(x)dx=1, 则 (int )_(0)^2xf(x)dx=

[题目]-|||-若 int f(x)dx=F(x)+C, 则 int f(2x-3)dx= __ .

【例4】已知函数f(x)在[-1,2]上连续，且int_(-1)^0f(x)dx=2，int_(0)^1f(2x)dx=1，则int_(-1)^2f(x)dx=

[题目]已知f((x)在 x=0 处可导,且 (0)=0, 则-|||-lim _(xarrow 0)dfrac ({x)^2f(x)-2f((x)^3)}({

[2023年真题]设连续函数f(x)满足： f(x+2)-f(x)=x,int_(0)^2f(x)dx=0,则 int_(1)^3f(x)dx=[2023年真题

[题目]已知f(x)在 x=0 处可导,且 (0)=0, 则-|||-lim _(xarrow 0)dfrac ({x)^2f(x)-2f((x)^3)}({x

5.已知 (x)=(x)^2+2(int )_(0)^2f(t)dt ,则 f(x)= __-|||-二