[题目]设连续函数f(x)满足 (x)=(x)^2-(int )_(0)^2f(x)dx ,则-|||-(int )_(0)^2f(x)dx=

[2023年真题]设连续函数f(x)满足： f(x+2)-f(x)=x,int_(0)^2f(x)dx=0,则 int_(1)^3f(x)dx=[2023年真题

设f(x)是连续函数,且 (x)=(x)^2+2(int )_(0)^2f(t)dt 则 f(x)=设f(x)是连续函数,且 (x)=(x)^2+2(int )

[题目]已知 (x)=(x)^2+(int )_(0)^2f(x)dx, 则∫f-|||-(x) = __ .

设 f(2)=4 , (int )_(0)^2f(x)dx=1, 则 (int )_(0)^2xf(x)dx=

3.已知 (int )_(0)^2f(x)dx=3 ,则 (int )_(0)^2[ f(x)+6] dx= __ 一

【例4】已知函数f(x)在[-1,2]上连续，且int_(-1)^0f(x)dx=2，int_(0)^1f(2x)dx=1，则int_(-1)^2f(x)dx=

设f(x)为连续函数，则(int )_(0)^1f(dfrac (x)(2))dx等于( )．(int )_(0)^1f(dfrac (x)(2))dx设f(x

设 f ( x ) 是连续奇函数且(int )_(0)^1f(x)dx=-2 则 (int )_(0)^1f(x)dx=-2设f(x)是连续奇函数且则

05 设f(u)为连续函数，且int_(0)^xtf(2x-t)dt=(1)/(2)(1+x^2)，f(1)=1.则int_(1)^2f(x)dx=A. $\f

【题目】-|||-设f(x)在 (-infty ,+infty ) 内连续,则 (int )_(2)^3f(x)dx+(int )_(3)^2f(t)dt+(i