设f(x)为连续函数,则(int )_(0)^1f'(dfrac (x)(2))dx等于( ).(int )_(0)^1f'(dfrac (x)(2))dx

设f(x)为连续函数,则等于( ).

参考答案与解析:

相关试题

[题目]设连续函数f(x)满足 (x)=(x)^2-(int )_(0)^2f(x)dx ,则-|||-(int )_(0)^2f(x)dx=

[题目]设连续函数f(x)满足 (x)=(x)^2-(int )_(0)^2f(x)dx ,则-|||-(int )_(0)^2f(x)dx=

  • 查看答案
  • 16、设 (int )_(0)^xf(t)dt=dfrac (1)(2)f(x)-dfrac (1)(2), 其中f(x)为连续函数,则 f(x)=()-|||-(A) ^dfrac (x{2)} (

    16、设 (int )_(0)^xf(t)dt=dfrac (1)(2)f(x)-dfrac (1)(2), 其中f(x)为连续函数,则 f(x)=()-|||

  • 查看答案
  • 设 f ( x ) 是连续奇函数且(int )_(0)^1f(x)dx=-2 则 (int )_(0)^1f(x)dx=-2

    设 f ( x ) 是连续奇函数且(int )_(0)^1f(x)dx=-2 则 (int )_(0)^1f(x)dx=-2设f(x)是连续奇函数且则

  • 查看答案
  • 设 f(2)=4 , (int )_(0)^2f(x)dx=1, 则 (int )_(0)^2xf'(x)dx=

    设 f(2)=4 , (int )_(0)^2f(x)dx=1, 则 (int )_(0)^2xf(x)dx=

  • 查看答案
  • 设(x)=dfrac (1)(1+{x)^2}+sqrt (1-{x)^2}(int )_(0)^1f(x)dx, 则 (int )_(0)^1f(x)dx=

    设(x)=dfrac (1)(1+{x)^2}+sqrt (1-{x)^2}(int )_(0)^1f(x)dx, 则 (int )_(0)^1f(x)dx=设

  • 查看答案
  • [2023年真题]设连续函数f(x)满足: f(x+2)-f(x)=x,int_(0)^2f(x)dx=0,则 int_(1)^3f(x)dx=

    [2023年真题]设连续函数f(x)满足: f(x+2)-f(x)=x,int_(0)^2f(x)dx=0,则 int_(1)^3f(x)dx=[2023年真题

  • 查看答案
  • 设 (x)=(e)^-x, 则 int dfrac (f'(ln x))(x)dx= .(x)=(e)^-x, 则 int dfrac (f'(ln x))(x)dx= .

    设 (x)=(e)^-x, 则 int dfrac (f(ln x))(x)dx= .(x)=(e)^-x, 则 int dfrac (f(ln x))(x)

  • 查看答案
  • [题目]-|||-设f(x)为连续函数,且 (x)=(int )_(dfrac {1)(x)}^ln xf(t)dt, 则F'(x)等于 ()-|||-(A) dfrac (1)(x)f(ln

    [题目]-|||-设f(x)为连续函数,且 (x)=(int )_(dfrac {1)(x)}^ln xf(t)dt, 则F(x)等于 ()-|||-(A) d

  • 查看答案
  • (4)若 (int )_(0)^1f(x)dx=agt 0, 则 (int )_(0)^1dfrac (1)(sqrt {x)}f(sqrt (x))dx=() .-|||-(A) dfrac (a)

    (4)若 (int )_(0)^1f(x)dx=agt 0, 则 (int )_(0)^1dfrac (1)(sqrt {x)}f(sqrt (x))dx=()

  • 查看答案
  • 2.设 '(x)=2, 且 f(0)=0 ,则 int f(x)dx= __-|||-

    2.设 (x)=2, 且 f(0)=0 ,则 int f(x)dx= __-|||-

  • 查看答案