[题目]-|||-设f(x)为连续函数,且 (x)=(int )_(dfrac {1)(x)}^ln xf(t)dt, 则F'(x)等于 ()-|||-(A) dfrac (1)(x)f(ln x)+dfrac (1)({x)^2}f(dfrac (1)(x)) (B) (ln x)+f(dfrac (1)(x))-|||-(C) dfrac (1)(x)f(ln x)-dfrac (1)({x)^2}f(dfrac (1)(x)) (D) (ln x)-f(dfrac (1)(x))

16、设 (int )_(0)^xf(t)dt=dfrac (1)(2)f(x)-dfrac (1)(2), 其中f(x)为连续函数,则 f(x)=()-|||

设 (x)=(e)^-x, 则 int dfrac (f(ln x))(x)dx= .(x)=(e)^-x, 则 int dfrac (f(ln x))(x)

设f(x)为连续函数，则(int )_(0)^1f(dfrac (x)(2))dx等于( )．(int )_(0)^1f(dfrac (x)(2))dx设f(x

[题目]设f(x)是连续函数,且 (x)=x+2(int )_(0)^1f(t)dt,-|||-则 f(x)= __

设(x)=dfrac ({x)^2}(x-a)(int )_(a)^xf(t)dt, 其中f(x)设(x)=dfrac ({x)^2}(x-a)(int )_(

14.设 (ln x)=1+dfrac (1)(x) ,且 f(0)=0 ,则 f(x)= __

1.已知 (x)=dfrac (1)(x(1+2ln x)) 且 f(1)=1, 则f(x)等于_ __-|||-

14.设f(x)的一个原函数是lnx,则 int dfrac (f(ln x))(x)dx= __

设lim _(xarrow 0)dfrac (ln (1+x+dfrac {f(x))(x))}(x)=3，则lim _(xarrow 0)dfrac (ln

设f(x)是连续函数,且 (x)=(x)^2+2(int )_(0)^2f(t)dt 则 f(x)=设f(x)是连续函数,且 (x)=(x)^2+2(int )