1.已知 '(x)=dfrac (1)(x(1+2ln x)) 且 f(1)=1, 则f(x)等于_ __-|||-

[题目]-|||-设f(x)为连续函数,且 (x)=(int )_(dfrac {1)(x)}^ln xf(t)dt, 则F(x)等于 ()-|||-(A) d

已知 函数 f ( x ) 满足 f ( -1 ) = 1 ，且lim _(xarrow 1)dfrac (f(x)-f(-1))(ax+a)=dfrac (

14.设 (ln x)=1+dfrac (1)(x) ,且 f(0)=0 ,则 f(x)= __

设 f(x) 在 x=1 处连续,且 dfrac (f(x)-2x)({e)^x-1-1}-dfrac (1)(ln x) 在 x=1-|||-的某去心邻域有界

1.设 (x)=dfrac (1)(1-{x)^2}, 求 (-x),f[ f(x)] ,f[ dfrac (1)(f(x))]

1.设f(x)为可导函数,且 lim _(xarrow 0)dfrac (f(1)-f(1-x))(2x)=-1 ,则 f(1)= __

已知f(x)满足 lim _(xarrow 1)dfrac (f(x))(ln x)=1, 则 () .-|||-(A) f(1)=0 (B) lim _(xa

1.设 (dfrac (1)(x))=x((dfrac {x)(x+1))}^2, 则 f(x)= ()-|||-(A) dfrac (1)(x)((dfrac

(1)已知 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则 f(x)= __ ;

1.已知f(x)满足2f(x)+f(1-x)=x²，则f(x)=1.已知f(x)满足2f(x)+f(1-x)=x²，则f(x)=