设(x)=dfrac ({x)^2}(x-a)(int )_(a)^xf(t)dt, 其中f(x)设(x)=dfrac ({x)^2}(x-a)(int )_(
[题目]-|||-设f(x)为连续函数,且 (x)=(int )_(dfrac {1)(x)}^ln xf(t)dt, 则F(x)等于 ()-|||-(A) d
设f(x)为连续函数,则(int )_(0)^1f(dfrac (x)(2))dx等于( ).(int )_(0)^1f(dfrac (x)(2))dx设f(x
设f(x)是连续函数,且 (x)=(x)^2+2(int )_(0)^2f(t)dt 则 f(x)=设f(x)是连续函数,且 (x)=(x)^2+2(int )
设f(x)连续,则 dfrac (d)(dx)(int )_(0)^xtf((x)^2-(t)^2)dt= ()-|||-A、xf(x^2)-|||-B、 -x
19.设f(x)连续,且 (int )_(0)^xtf(2x-t)dt=dfrac (1)(2)arctan (x)^2 (1)=1, 则 (int )_(1)
[题目]设函数f(x)连续,则 dfrac (d)(dx)(int )_(0)^xtf((t)^2-(x)^2)dt= __-|||-_.
[题目]设f(x)是连续函数,且 (x)=x+2(int )_(0)^1f(t)dt,-|||-则 f(x)= __
34.设函数f(x)为连续函数,且有int_(0)^x^(2)f(t)dt=x^4+x^2,则f(2)=()A. 0B. 2C. 3D. 5
2.设函数 (x)=dfrac (1)(x) ,则 f[ f(x)] =