19.设f(x)连续,且 (int )_(0)^xtf(2x-t)dt=dfrac (1)(2)arctan (x)^2 (1)=1, 则 (int )_(1)^2f(x)dx= __

05 设f(u)为连续函数，且int_(0)^xtf(2x-t)dt=(1)/(2)(1+x^2)，f(1)=1.则int_(1)^2f(x)dx=A. $\f

(8)设f(x)连续,则 dfrac (d)(dx)(int )_(0)^xtf((x)^2-(t)^2)dt= __

设f(x)是连续函数,且 (x)=(x)^2+2(int )_(0)^2f(t)dt 则 f(x)=设f(x)是连续函数,且 (x)=(x)^2+2(int )

[题目]设函数f(x)连续,则 dfrac (d)(dx)(int )_(0)^xtf((t)^2-(x)^2)dt= __-|||-_.

16、设 (int )_(0)^xf(t)dt=dfrac (1)(2)f(x)-dfrac (1)(2), 其中f(x)为连续函数,则 f(x)=()-|||

【例4】已知函数f(x)在[-1,2]上连续，且int_(-1)^0f(x)dx=2，int_(0)^1f(2x)dx=1，则int_(-1)^2f(x)dx=

设 f ( x ) 是连续奇函数且(int )_(0)^1f(x)dx=-2 则 (int )_(0)^1f(x)dx=-2设f(x)是连续奇函数且则

设(x)=dfrac (1)(1+{x)^2}+sqrt (1-{x)^2}(int )_(0)^1f(x)dx, 则 (int )_(0)^1f(x)dx=设

设f(x)连续,且 (x)=x+2(int )_(0)^1f(t)dt, 则 f(x)= __

设 f(2)=4 , (int )_(0)^2f(x)dx=1, 则 (int )_(0)^2xf(x)dx=