设(x)=dfrac ({x)^2}(x-a)(int )_(a)^xf(t)dt, 其中f(x)设(x)=dfrac ({x)^2}(x-a)(int )_(a)^xf(t)dt, 其中f(x)

求下列极限： (1) lim _(xarrow a)dfrac (x)(x-a)(int )_(a)^xf(t)dt, 其中f(x)连续; (1) li

16、设 (int )_(0)^xf(t)dt=dfrac (1)(2)f(x)-dfrac (1)(2), 其中f(x)为连续函数,则 f(x)=()-|||

设f(x)连续,则 dfrac (d)(dx)(int )_(0)^xtf((x)^2-(t)^2)dt= ()-|||-A、xf(x^2)-|||-B、 -x

[题目]-|||-设f(x)为连续函数,且 (x)=(int )_(dfrac {1)(x)}^ln xf(t)dt, 则F(x)等于 ()-|||-(A) d

设f(x)在[a，b]上连续，F(x)=(int )_(a)^xf(t)dt，则(,)A. $F\left(x\right)$是$f\left(x\right)

设 gt 0 时 f(x)可导,且满足 (x)=1+dfrac (1)(x)(int )_(1)^xf(t)dt, 求 f(x).

设f(x)可微，且满足=(int )_(0)^xf(t)dt+(int )_(0)^xtf(t-x)dt，则f(x)=．设f(x)可微，且满足，则f(x)=．

分) 设 (x)=(int )_({x)^2}dfrac (t)(sqrt {1+{t)^3}}dt 求 =(int )_(0)^1xF(x)dx

设f(x)在 [ 0,+infty ) 上非负连续,且 (x)(int )_(0)^xf(x-t)dt=2(x)^3, 则 f(x)=

12.设函数f(x)连续，且满足f(x)=e^x+int_(0)^xtf(t)dt-xint_(0)^xf(t)dt，求f(x).12.设函数f(x)连续，且满