设 gt 0 时 f(x)可导,且满足 (x)=1+dfrac (1)(x)(int )_(1)^xf(t)dt, 求 f(x).

19.函数f(x)在 [ 0,+infty ) 上可导, (0)=1, 且满足等式-|||-(x)+f(x)-dfrac (1)(x+1)(int )_(0)^

8、已知f(x)在(-∞,+∞)上可导，且满足方程xf(x)-4int_(1)^xf(t)dt=x^3-3，求f(x).8、已知f(x)在(-∞,+∞)上可导，

设f(x)可微，且满足=(int )_(0)^xf(t)dt+(int )_(0)^xtf(t-x)dt，则f(x)=．设f(x)可微，且满足，则f(x)=．

16、设 (int )_(0)^xf(t)dt=dfrac (1)(2)f(x)-dfrac (1)(2), 其中f(x)为连续函数,则 f(x)=()-|||

设(x)=dfrac ({x)^2}(x-a)(int )_(a)^xf(t)dt, 其中f(x)设(x)=dfrac ({x)^2}(x-a)(int )_(

[题目]-|||-设f(x)为连续函数,且 (x)=(int )_(dfrac {1)(x)}^ln xf(t)dt, 则F(x)等于 ()-|||-(A) d

12.设函数f(x)连续，且满足f(x)=e^x+int_(0)^xtf(t)dt-xint_(0)^xf(t)dt，求f(x).12.设函数f(x)连续，且满

设f(x)连续, varphi (x)=(int )_(0)^1f(xt)dt, 且 lim _(xarrow 0)dfrac (f(x))(x)=A设f(x)

求下列极限： (1) lim _(xarrow a)dfrac (x)(x-a)(int )_(a)^xf(t)dt, 其中f(x)连续; (1) li

设f(x)在[a，b]上连续，在(a，b)内可导，且f(x)≤0，F(x)=dfrac(1)(x-a)int_(a)^x(f(t)dt), 证明：在(a，b)内