判断题:tan x)=(sec )^2xtan x)=(sec )^2x 正确 tan x)=(sec )^2x 错误判断题:正确错误
求下列不定积分:-|||-(22) int dfrac (cos 2x)({cos )^2x(sin )^2x}dx ;
y=(sin )^2(2-3x),则dy=(,,,,,)A、sin (4-6x)dxB、(cos )^2(2-3x)dxC、-3sin (4-6x)dxD、-3
(tan x)^prime=1/(cos x)^2=(sec x)^2=( )题型说明:共15题,每题2分。26. (2.0分) $(\tan x)^{\pri
f(x)=(cos )^23x,则f(3x)=(,,,,,)A、-3sin (6x)B、-3sin (18x)C、-9sin (18x)D、-9sin (6x)
(6) lim _(xarrow 0)dfrac (sqrt {1+tan x)-sqrt (1+sin x)}(xsqrt {1+{sin )^2x}-x}
设函数为(x)=3(x)^2-2x+1-|||-__,则 f( x ) 的值为 A 6 x - 2 B (x)=3(x)^2-2x+1-|||-__C 6 x
(B.) y = (1)/(2)x^2e^2x + sin 2x. (C.) y = (x)/(2)(x + 4)e^3x. (D.) y = (x^2co
[题目]如果 f(x)= () ,那么 (x)=0-|||-A、 arcsin 2x+axccos x-|||-B、 (sec )^2+(tan )^2x-||
4.设 =(x)^3(y)^2+3, 则 dfrac ({partial )^2z}(partial ypartial x)= () .-|||-(A)6x^2