求下列各极限:-|||-lim 1+tanx-√1+sinx

(3)lim-1+tanx -√1+sinx

计算下列极限。-|||-lim- 1+tanx-√1+sin x

2 求极限lim tanx-sinx

求极限underset(lim)(x→0)cotx（(1)/(sinx)-(1)/(x)）求极限$\underset{lim}{x→0}$cotx（$\frac

lim tanx-sinx

求极限lim-x-tanx-|||--tan x.求极限.

求极限underset(lim)(x→0)(（1-cosx）[x-ln（1+tanx）])/(si(n)^4x)．求极限$\underset{lim}{x→0}

用洛必达法则求下列极限:-|||-(13) lim _(xarrow 1)(dfrac (2)({x)^2-1}-dfrac (1)(x-1)) ;-|||-(

1.利用洛必达法则求下列极限-|||-1) lim sinx-x cosx-|||-x →0 sin3x

函数y=(cosx)/(1+sinx)的导数是（ ）A. $\frac{1}{1+sinx}$B. $-\frac{1}{1+sinx}$C. $\frac{s