设总体sim N(0,1) X1,X2,···,X6是来自总体X的简单随机样本sim N(0,1) X1,X2,···,X6分别为样本均值和样本方差sim N(
[题目]设x1,x2,...,x5是总体 approx N(0,1) 的简单-|||-随机样本,则当 k=_ 时, =dfrac (k({x)_(1)+(x)_
5.设X1,X2,X3,X4是总体 sim N(0,1) 的简单随机样本,则 =dfrac (sqrt {3)(X)_(1)}(sqrt {{{X)_(2)}^
4.设X1,X2,···,Xn为来自正态总体 sim N(0,1) 的简单随机样本, overline (X)=dfrac (1)(n)sum _(i=1)^n
设总体 sim N(0,2) ,(X1,X2,···,X6)是来-|||-自总体X的样本,若 dfrac (a({X)_(1)+(X)_(2))}(sqrt {
总体sim N(0,1), X1,X2,X3,X4,X55,X6,X7,X8为来自总体sim N(0,1), X1,X2,X3,X4,X55,X6,X7,X8的
10.设总体 sim N(0,1), X1,X2,X3是来自X的样本,则 =dfrac (sqrt {3)X}(sqrt {{{X)_(1)}^2+({X)_(
设总体sim N(0,1) ,X1,X2,···X5为来自总体的样本,令sim N(0,1) ,X1,X2,···X5则下列说法错误的是( )sim N(0,1
7.设X1,X2,···, _(n)(ngeqslant 2) 为来自正态总体N(μ,1)的简单随机样本,若 overline (X)=-|||-dfrac (
22.设X1,X2,···,x6是来自总体N(0,1 )的样本,则 _(1)sim ()-|||-(A)N(0,1) (B)N(0,6) (C)x^2(1) (