_(0)=2;-|||-(3) dfrac (1)({2)^2} , _(0)=-1;-|||-(4) dfrac (1)(4-3z), _(0)=1+i;-|||-(5)tanz, _(0)=dfrac (pi )(4);-|||-(6)arctanz, _(0)=0.

参考答案与解析：

相关试题

4.7求下列函数在指定点z0处的泰勒展式:-|||-(1) 1/(x^2) _(0)=1 ;-|||-(2)sin z, _(0)=1 ;-|||-(3) dfrac (1)(4-3z), _(0)=

4.7求下列函数在指定点z0处的泰勒展式:-|||-(1) 1/(x^2) _(0)=1 ;-|||-(2)sin z, _(0)=1 ;-|||-(3) df

  • 查看答案

    • 4.设 (z)=dfrac (1)(z)-zsin dfrac (1)({z)^2}, 则 [ f(z),0] =-|||-(A)1; (B)2; (C)0; (D)2πi.

    4.设 (z)=dfrac (1)(z)-zsin dfrac (1)({z)^2}, 则 [ f(z),0] =-|||-(A)1; (B)2; (C)0;

  • 查看答案

    • 1 0 0-|||-、已知A= 0 dfrac (1)(2) dfrac (3)(2) 求([ {({A)^*)}^T] }^-1-|||-0 1 5/2

    1 0 0-|||-、已知A= 0 dfrac (1)(2) dfrac (3)(2) 求([ {({A)^*)}^T] }^-1-|||-0 1 5/2

  • 查看答案

    • 设矩阵1 0 0-|||-=dfrac (1)(2) __ 0 2 1-|||-0 3 2，则1 0 0-|||-=dfrac (1)(2) __ 0 2 1-|||-0 3 2。1 0 0-|||-

    设矩阵1 0 0-|||-=dfrac (1)(2) __ 0 2 1-|||-0 3 2，则1 0 0-|||-=dfrac (1)(2) __ 0 2 1-

  • 查看答案

    • 23、 图路-|||-设矩阵A= -2 0 0 7 1 -3 0 -1 -4 1 B= [ dfrac -|||-A |-dfrac (1)(6)(A)^3(B)^r|=((-dfrac {1)

    23、 图路-|||-设矩阵A= -2 0 0 7 1 -3 0 -1 -4 1 B= [ dfrac -|||-A |-dfrac (1)(6)(A)^

  • 查看答案

    • 设二维随机变量(X,Y)的分布律为-|||-Y 0 1 2-|||-0 dfrac (1)(4) 0 dfrac (1)(4)-|||-1 0 dfrac (1)(3) 0-|||-2 dfrac (

    设二维随机变量(X,Y)的分布律为-|||-Y 0 1 2-|||-0 dfrac (1)(4) 0 dfrac (1)(4)-|||-1 0 dfrac (1

  • 查看答案

    • 4.7 求下列函数在指定点z0处的泰勒展式:-|||-(1) dfrac (1)({z)^2} ,_(0)=1 ;-|||-(2)sinz, _(0)=1 ;-|||-(3) dfrac (1)(4-

    4.7 求下列函数在指定点z0处的泰勒展式:-|||-(1) dfrac (1)({z)^2} ,_(0)=1 ;-|||-(2)sinz, _(0)=1 ;-

  • 查看答案

    • A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)

    A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)设

  • 查看答案

    • 1.1 计算下列各式.-|||-(1) (1+i)-(3-2i);-|||-(2) ((a-ib))^3;-|||-(3) dfrac (1)((i-1)(i-2));-|||-(4) dfrac (

    1.1 计算下列各式.-|||-(1) (1+i)-(3-2i);-|||-(2) ((a-ib))^3;-|||-(3) dfrac (1)((i-1)(i-

  • 查看答案

    • _(1)=5-5i, () _(2)=-3+4i 罒 (dfrac ({z)_(1)}({z)_(2)}) (整体取共-|||-A -dfrac (7)(5)-dfrac (1)(5)-|||-B)

    _(1)=5-5i, () _(2)=-3+4i 罒 (dfrac ({z)_(1)}({z)_(2)}) (整体取共-|||-A -dfrac (7)(5)-

  • 查看答案