A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)

1.9 利用复数的三角表示计算下列各式:-|||-(1) (1+i)(1-i) ;-|||-(2) (-2+3i)/(3+2i) ;-|||-(3) ((dfr

设(z)=1-overline (z), _(1)=2+3i _(2)=5-i, 则 ([ f({z)_(1)-(z)_(2))-|||-__等于设等于

已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {

_(1)=5-5i, () _(2)=-3+4i 罒 (dfrac ({z)_(1)}({z)_(2)}) (整体取共-|||-A -dfrac (7)(5)-

dfrac ((x+1)+i(y-3))(5+3i)=1+i ，则实部dfrac ((x+1)+i(y-3))(5+3i)=1+i，虚部 dfrac ((x+1

若((dfrac {a+i)(1-i))}^2=-1，则a=；A 0 B 2 C 1 D 3若，则a=；A0B2C1D3

1.1计算下列各式.-|||-(1) (1+i)-(3-2i) ;-|||-(2) ((a-ib))^3 ;-|||-(3) dfrac (i)((i-1)(i

1.1 计算下列各式.-|||-(1) (1+i)-(3-2i);-|||-(2) ((a-ib))^3;-|||-(3) dfrac (1)((i-1)(i-

(D) =dfrac ({mu )_(0)(I)_(1)(I)_(2)}(2pi )ln dfrac (b)(a)-|||-Ai-|||-I1-|||-C I2

求下列各复数的实部、虚部、模与幅角。(1)dfrac (1-2i)(3-4i)-dfrac (2-i)(5i);求下列各复数的实部、虚部、模与幅角。(1);