(D) =dfrac ({mu )_(0)(I)_(1)(I)_(2)}(2pi )ln dfrac (b)(a)-|||-Ai-|||-I1-|||-C I2 D-|||-a _ b--|||-l2-|||-B-|||-图 -2 图 5-3

参考答案与解析：

相关试题

(B) .dfrac ({mu )_(0)I}(2pi R)+dfrac (3{mu )_(0)I}(8R)-|||-(c) dfrac ({mu )_(0)I}(4pi R)-dfrac (3{mu

(B) .dfrac ({mu )_(0)I}(2pi R)+dfrac (3{mu )_(0)I}(8R)-|||-(c) dfrac ({mu )_(0)I

  • 查看答案

    • dfrac ({U)_(0)I}(2R)-|||-D . dfrac ({U)_(0)I}(2pi R)

    dfrac ({U)_(0)I}(2R)-|||-D . dfrac ({U)_(0)I}(2pi R)

  • 查看答案

    • (B) (mu ,dfrac (1)(sqrt {2pi )})-|||-(C) (mu ,dfrac (1)(2)), (D)(0,σ).

    (B) (mu ,dfrac (1)(sqrt {2pi )})-|||-(C) (mu ,dfrac (1)(2)), (D)(0,σ).

  • 查看答案

    • dfrac ({mu )_(0)I}(pi R)(dfrac (1)(2)+dfrac (pi )(6))-|||-dfrac ({mu )_(0)I}(pi R)(1-dfrac (sqrt {3)

    dfrac ({mu )_(0)I}(pi R)(dfrac (1)(2)+dfrac (pi )(6))-|||-dfrac ({mu )_(0)I}(pi

  • 查看答案

    • A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)

    A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)设

  • 查看答案

    • 若((dfrac {a+i)(1-i))}^2=-1，则a=；A 0 B 2 C 1 D 3

    若((dfrac {a+i)(1-i))}^2=-1，则a=；A 0 B 2 C 1 D 3若，则a=；A0B2C1D3

  • 查看答案

    • 已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {3)i}

    已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {

  • 查看答案

    • dfrac (qQ)(4pi {varepsilon )_(0)(d)_(1)} B. dfrac (qQ)(2pi {varepsilon )_(0)(d)_(1)} C. dfrac (qQ)(2

    dfrac (qQ)(4pi {varepsilon )_(0)(d)_(1)} B. dfrac (qQ)(2pi {varepsilon )_(0)(d)_

  • 查看答案

    • 4.设 (z)=dfrac (1)(z)-zsin dfrac (1)({z)^2}, 则 [ f(z),0] =-|||-(A)1; (B)2; (C)0; (D)2πi.

    4.设 (z)=dfrac (1)(z)-zsin dfrac (1)({z)^2}, 则 [ f(z),0] =-|||-(A)1; (B)2; (C)0;

  • 查看答案

    • (B) dfrac (1)(n+1)sum _(i=1)^n(({X)_(i)-overline (X))}^2 .-|||-(C) dfrac (1)(n)sum _(i=1)^n({X)_(i)}

    (B) dfrac (1)(n+1)sum _(i=1)^n(({X)_(i)-overline (X))}^2 .-|||-(C) dfrac (1)(n)s

  • 查看答案