已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {3)i}

复数=dfrac ((sqrt {3)+i)(2-2i)}((sqrt {3)-i)(2+2i)}的三角形式为( )=dfrac ((sqrt {3)+i)(2

1.1.18 就以下各种情况,分别求arg z:-|||-(a) =dfrac (-2)(1+sqrt {3)i} ;-|||-(b) =dfrac (i)(-

7.计算下列复数的值:-|||-(1) _(1)=((dfrac {-1+sqrt {3)i}(2))}^6;

复数=-2-2i的三角表示为=-2-2i=-2-2i=-2-2i=-2-2i复数的三角表示为

不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (

1.9 利用复数的三角表示计算下列各式:-|||-(1) (1+i)(1-i) ;-|||-(2) (-2+3i)/(3+2i) ;-|||-(3) ((dfr

1.1.19 利用复数的三角表达式或指数表达式证明:-|||-(a) ((-1+i))^7=-8(1+i);-|||-(b) ((1+sqrt {3)i)}^-

dfrac ({mu )_(0)I}(pi R)(dfrac (1)(2)+dfrac (pi )(6))-|||-dfrac ({mu )_(0)I}(pi

已知晶体原胞基矢为:overrightarrow ({a)_(1)}=dfrac (a)(2)overrightarrow (i)+dfrac (sqrt {3

A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)设