求下列各复数的实部、虚部、模与幅角。(1)dfrac (1-2i)(3-4i)-dfrac (2-i)(5i);

1.求下列复数z的实部与虚部、共轭复数、模与辐角:-|||-(1) 1/(3+2i);-|||-(2) dfrac (1)(i)-dfrac (3i)(1-i)

求复数=dfrac (2i)(1-i)+dfrac (2(1-i))(i)的模与主辐角。求复数的模与主辐角。

dfrac ((x+1)+i(y-3))(5+3i)=1+i ，则实部dfrac ((x+1)+i(y-3))(5+3i)=1+i，虚部 dfrac ((x+1

2(2020·全国Ⅲ)复数 dfrac (1)(1-3i) 的虚部是 () 。-|||-

已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {

A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)设

1.1计算下列各式.-|||-(1) (1+i)-(3-2i) ;-|||-(2) ((a-ib))^3 ;-|||-(3) dfrac (i)((i-1)(i

1.9 利用复数的三角表示计算下列各式:-|||-(1) (1+i)(1-i) ;-|||-(2) (-2+3i)/(3+2i) ;-|||-(3) ((dfr

1.1 计算下列各式.-|||-(1) (1+i)-(3-2i);-|||-(2) ((a-ib))^3;-|||-(3) dfrac (1)((i-1)(i-

复数=dfrac ((sqrt {3)+i)(2-2i)}((sqrt {3)-i)(2+2i)}的三角形式为( )=dfrac ((sqrt {3)+i)(2