1.求下列复数z的实部与虚部、共轭复数、模与辐角:-|||-(1) 1/(3+2i);-|||-(2) dfrac (1)(i)-dfrac (3i)(1-i);-|||-(3) dfrac ((3+4i)(2-5i))(2i);-|||-(4) https:/img.zuoyebang.cc/zyb_f4c780ed2ac2d743fc2449876c657113.jpg^8-(4i)^21+i.

dfrac (1)(z)-dfrac (3i)(1-i)的共轭复数为 dfrac (1)(z)-dfrac (3i)(1-i) D.以上都不对的共轭复数为D.以

求复数=dfrac (2i)(1-i)+dfrac (2(1-i))(i)的模与主辐角。求复数的模与主辐角。

求下列各复数的实部、虚部、模与幅角。(1)dfrac (1-2i)(3-4i)-dfrac (2-i)(5i);求下列各复数的实部、虚部、模与幅角。(1);

1.9 利用复数的三角表示计算下列各式:-|||-(1) (1+i)(1-i) ;-|||-(2) (-2+3i)/(3+2i) ;-|||-(3) ((dfr

2(2020·全国Ⅲ)复数 dfrac (1)(1-3i) 的虚部是 () 。-|||-

已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {

1.6 求下列复数的模与辐角主值:-|||-(1) sqrt (3)+i;-|||-(2) -1-1;-|||-(3) -i;-|||-(4) -1+31.

dfrac ((x+1)+i(y-3))(5+3i)=1+i ，则实部dfrac ((x+1)+i(y-3))(5+3i)=1+i，虚部 dfrac ((x+1

考题9 设i是虚数单位,z表示复数z的共轭复数.若-|||-=1+i, 则 dfrac (z)(i)+icdot overline (z)= () .-|||-

A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)设