dfrac (1)(z)-dfrac (3i)(1-i)的共轭复数为 dfrac (1)(z)-dfrac (3i)(1-i) D.以上都不对

1.求下列复数z的实部与虚部、共轭复数、模与辐角:-|||-(1) 1/(3+2i);-|||-(2) dfrac (1)(i)-dfrac (3i)(1-i)

求复数=dfrac (2i)(1-i)+dfrac (2(1-i))(i)的模与主辐角。求复数的模与主辐角。

考题9 设i是虚数单位,z表示复数z的共轭复数.若-|||-=1+i, 则 dfrac (z)(i)+icdot overline (z)= () .-|||-

若((dfrac {a+i)(1-i))}^2=-1，则a=；A 0 B 2 C 1 D 3若，则a=；A0B2C1D3

[单选题]复数z满足(1+i)z=1-i，则|Z|=()。A.√2/2B.√2C.2D.1

_(1)=5-5i, () _(2)=-3+4i 罒 (dfrac ({z)_(1)}({z)_(2)}) (整体取共-|||-A -dfrac (7)(5)-

已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {

[问答题]若复数z=a/(1-i)+(1-i)/2是纯虚数，则实数a等于________。

1.9 利用复数的三角表示计算下列各式:-|||-(1) (1+i)(1-i) ;-|||-(2) (-2+3i)/(3+2i) ;-|||-(3) ((dfr

A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)设