dfrac ((x+1)+i(y-3))(5+3i)=1+i ，则实部dfrac ((x+1)+i(y-3))(5+3i)=1+i，虚部 dfrac ((x+1)+i(y-3))(5+3i)=1+i 分别为多少 A 1 , 12 B 1 , 11 C 2 , 15 D 2 , 7

1、已知方程x+1+i(y-3)=(1+i)(5+3i)，则x=____，y=____。1、已知方程$x+1+i(y-3)=(1+i)(5+3i)$，则x=__

1.1计算下列各式.-|||-(1) (1+i)-(3-2i) ;-|||-(2) ((a-ib))^3 ;-|||-(3) dfrac (i)((i-1)(i

1.1 计算下列各式.-|||-(1) (1+i)-(3-2i);-|||-(2) ((a-ib))^3;-|||-(3) dfrac (1)((i-1)(i-

A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)设

18.求 e^1-i(pi)/(2),exp[(1+iπ)/4],3^i和(1+i)^i 的值.18.求 $e^{1-i\frac{\pi}{2}}$,exp[

1.9 利用复数的三角表示计算下列各式:-|||-(1) (1+i)(1-i) ;-|||-(2) (-2+3i)/(3+2i) ;-|||-(3) ((dfr

1.求下列复数z的实部与虚部、共轭复数、模与辐角:-|||-(1) 1/(3+2i);-|||-(2) dfrac (1)(i)-dfrac (3i)(1-i)

求下列各复数的实部、虚部、模与幅角。(1)dfrac (1-2i)(3-4i)-dfrac (2-i)(5i);求下列各复数的实部、虚部、模与幅角。(1);

已知复数=dfrac (2-2i)(1+sqrt {3)i}，则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {

_(0)=2;-|||-(3) dfrac (1)({2)^2} , _(0)=-1;-|||-(4) dfrac (1)(4-3z), _(0)=1+i;-|