6.求积分int_(0)^2pi a(2z^2+8z+1)dz之值,其中积分路径是连接0到2πa的摆线:x=a(theta-sintheta),y=a(1-co
设 C: |z+1|=(1)/(2),则 int_(C) (sin frac(pi)/(4) z)(z^2-1) dz=A. $2\pi i$B. $-\fra
曲线 C 为正向圆周 |z-1|=3,int_(C) (1)/(z^3(z-2)^2) , dz=A. $\frac{3}{8}\pi i$B. $\frac{
设 C 为正向圆周 |z|=2,则 int_(C) (z+e^z)/((z+1)^4) dz = ( )A. $\frac{\pi i}{3e}$B. $\fr
曲线C是自0至1+i的直线段,则int_(C)e^|z|^2(Re)z,dz=()A. $\frac{1}{4}(e^2+1)(1-i)$B. $\frac{1
设mathbb(C)为正向圆周|z|=1,则int_(mathbb{C)} z , dz = ( ).A. $6\pi i$;B. $4\pi i$;C. $2
(8) int_(0)^pi(1-sin ^3theta )dtheta(8) $\int_{0}^{\pi}(1-\sin ^{3}\theta )d\the
计算(int )_(c)_(c)dfrac (cos z)((z-dfrac {1)(2))(z-1)}dz,其中(int )_(c)_(c)dfrac (co
定积分int_(0)^(pi)/(4)sec^2xdx=11.(填空题,5.0分)定积分$\int_{0}^{\frac{\pi}{4}}sec^{2}xdx=
int_(0)^1(2x+x^3)dx=() A -1 B (5)/(4) C 1 D 026. (2.