A. $2\pi i$
B. $-\frac{\sqrt{2}}{2} \pi i$
C. $\sqrt{2} \pi i$
D. $\frac{\sqrt{2}}{2} \pi i$
设 C 为正向圆周 |z|=2,则 int_(C) (z+e^z)/((z+1)^4) dz = ( )A. $\frac{\pi i}{3e}$B. $\fr
设mathbb(C)为正向圆周|z|=1,则int_(mathbb{C)} z , dz = ( ).A. $6\pi i$;B. $4\pi i$;C. $2
曲线 C 为正向圆周 |z-1|=3,int_(C) (1)/(z^3(z-2)^2) , dz=A. $\frac{3}{8}\pi i$B. $\frac{
12.求积分int_(C)(1)/(z+2)dz的值,其中C:|z|=1,并由此证明int_(0)^pi(1+2costheta)/(5+4costheta)d
计算(int )_(c)_(c)dfrac (cos z)((z-dfrac {1)(2))(z-1)}dz,其中(int )_(c)_(c)dfrac (co
设C:|z-2|=5为正向圆周,则int dfrac (2{z)^3+3(z)^2+2z+1}(z)dz=()A、2πіB、πі; C、i;D、0;设C:|z-
曲线C是自0至1+i的直线段,则int_(C)e^|z|^2(Re)z,dz=()A. $\frac{1}{4}(e^2+1)(1-i)$B. $\frac{1
(z)=(z)^2+dfrac (1)({z)^2-1},则其解析区域为()(z)=(z)^2+dfrac (1)({z)^2-1}(z)=(z)^2+dfra
12.计算下列各积分,C为正向圆周:1)oint(z^15)/((z^2)+1)^(2(z^4+2)^3)dz,C:|z|=3;2)oint(z^3)/(1+z
(7)oint(dz)/((z^2)+1)(z^(2+4)),C:|z|=3/2(7)$\oint\frac{dz}{(z^{2}+1)(z^{2}+4)}$,