15、计算积分oint_(C)(1)/((z-1)^3)(z-2)^(4(z-4))dz(曲线C:|z|=3为正向圆周).解:奇点2,1,4,∞(1分)oint
计算积分oint_(c)(1)/(z^101)(1-z^(2))dz,C为正向圆周|z|=1/2.计算积分$\oint_{c}\frac{1}{z^{101}(
(7)oint(dz)/((z^2)+1)(z^(2+4)),C:|z|=3/2(7)$\oint\frac{dz}{(z^{2}+1)(z^{2}+4)}$,
曲线 C 为正向圆周 |z-1|=3,int_(C) (1)/(z^3(z-2)^2) , dz=A. $\frac{3}{8}\pi i$B. $\frac{
曲线C为正向圆周|z|=2, (int )_(c)dfrac (cos z)({(z-1))^3}dz=曲线C为正向圆周A.0B.C.D.
5.[单选题]设C为正向圆周|z|=2,则oint_(c)(cos z)/((z-1)^2)dz等于()A. (A)-sin1;B. (B)0;C. (C)co
设 C 为正向圆周 |z|=2,则 int_(C) (z+e^z)/((z+1)^4) dz = ( )A. $\frac{\pi i}{3e}$B. $\fr
设C:|z-2|=5为正向圆周,则int dfrac (2{z)^3+3(z)^2+2z+1}(z)dz=()A、2πіB、πі; C、i;D、0;设C:|z-
曲线C为正向圆周|z-1|=3, (int )_(c)^3dfrac (3)(2)dz=|z-1|=3, (int )_(c)^3dfrac (3)(2)dz=
5.利用留数计算下列积分.-|||-(3) (int )_(|z|=2)dfrac ({e)^2z}((z+1){(z-1))^2}dz