设C:|z-2|=5为正向圆周,则
A、2πіB、πі; C、i;D、0;
设C:|z-2|=5为正向圆周,则
A、2πіB、πі; C、i;D、0;
曲线 C 为正向圆周 |z-1|=3,int_(C) (1)/(z^3(z-2)^2) , dz=A. $\frac{3}{8}\pi i$B. $\frac{
曲线C为正向圆周|z|=2, (int )_(c)dfrac (cos z)({(z-1))^3}dz=曲线C为正向圆周A.0B.C.D.
曲线C为正向圆周|z-1|=3, (int )_(c)^3dfrac (3)(2)dz=|z-1|=3, (int )_(c)^3dfrac (3)(2)dz=
设 C 为正向圆周 |z|=2,则 int_(C) (z+e^z)/((z+1)^4) dz = ( )A. $\frac{\pi i}{3e}$B. $\fr
12.计算下列各积分,C为正向圆周:1)oint(z^15)/((z^2)+1)^(2(z^4+2)^3)dz,C:|z|=3;2)oint(z^3)/(1+z
3.6 计算 (int )_(c)dfrac (1)({z)^2-z}dz, 其中C为圆周 |z|=2.
11.(单选题) 设C为正向圆周|z|=2,则oint_(c)(bar(z))/(z^2)dz=( ) A (A.)-2πi; B (B.) 0;
4.设 (z)=dfrac (1)(z)-zsin dfrac (1)({z)^2}, 则 [ f(z),0] =-|||-(A)1; (B)2; (C)0;
5.[单选题]设C为正向圆周|z|=2,则oint_(c)(cos z)/((z-1)^2)dz等于()A. (A)-sin1;B. (B)0;C. (C)co
计算(int )_(c)_(c)dfrac (cos z)((z-dfrac {1)(2))(z-1)}dz,其中(int )_(c)_(c)dfrac (co