设gt bgt 0 gt 1，证明 gt bgt 0 gt 1

设 gt bgt 0 ,n>1, 证明:-|||-nb^(n-1)(a-b)

证明下列不等式:-|||-设 gt bgt 0 ,n>1, 证明:-|||-(b)^n-1(a-b)lt (a)^n-(b)^nlt n(a)^n-1(a-b)

[题目]设 gt bgt 0 ,证明: dfrac (a-b)(a)lt ln dfrac (a)(b)lt dfrac (a-b)(b)

[题目]设 gt bgt 0, 证明: dfrac (a-b)(a)lt ln dfrac (a)(b)lt dfrac (a-b)(b).

[题目]设 gt bgt 0 ,证明: dfrac (a-b)(a)lt ln dfrac (a)(b)lt dfrac (a-b)(b)

一、填空题(本题共2小题)-|||-1.下列不等式中成立的是 __-|||-①若 gt bgt 0 则 (c)^2gt b(c)^2; ②若 gt bgt 0,

11.设 gt bgt 0, 证明:-|||-dfrac (a-b)(a)lt ln dfrac (a)(b)lt dfrac (a-b)(b)

1.-|||-证明:当 gt 0 时, gt ln (1+x)

二、多项选择题-|||-9.若 gt bgt 0 lt clt 0, 则下列不等式成立的是 ()-|||-

[题目]证明当 gt 0 时, (1+x)ln (1+x)gt x