设 gt bgt 0 ,n>1, 证明:-|||-nb^(n-1)(a-b)
的值为 .-|||-n-1 0 ...0 0 0-|||-0 0 ...0 0 n-|||-A ((-1))^dfrac ((n-1)(n-2){2)n!}!-
11.设n阶方阵A的伴随矩阵为A`,证明:-|||-(1) |A|=(|A|)^n-1.-|||-(2) (A)= ) n,R(A)=n, 1,R(A)=n
n-1 n-|||-1 2 ... n-1 0-|||-::-|||-1 2 ... 0 0-|||- ... 0 0;;
-a-|||-1 2 3 n-|||-1 1+2 3 n-|||-1 2 2+3 n =(n-1)!;-|||-1 2 3 (n-1)+n-|||-o
0 n-|||--1 -2 -3 . -(n-1) 0-|||-__计算行列式
+(a)_(n-1)x=0 有一个正根 =(x)_(0) ,证明方程 _(0)n(x)^n-1+(a)_(1)(n-1)(x)^n-2+... +(a)_(n-
[题目]设 gt bgt 0, 证明: dfrac (a-b)(a)lt ln dfrac (a)(b)lt dfrac (a-b)(b).
[题目]设 gt bgt 0 ,证明: dfrac (a-b)(a)lt ln dfrac (a)(b)lt dfrac (a-b)(b)
[题目]设 gt bgt 0 ,证明: dfrac (a-b)(a)lt ln dfrac (a)(b)lt dfrac (a-b)(b)