-a-|||-1 2 3 n-|||-1 1+2 3 n-|||-1 2 2+3 n =(n-1)!;-|||-1 2 3 (n-1)+n-|||-o

0 n-|||--1 -2 -3 . -(n-1) 0-|||-__计算行列式

n-|||-2 3 4 ... 1-|||-三、计算n阶行列式 3 4 5 ... 2 。-|||-......... .......-|||-n 1 2 ..

n-1 n-|||-1 2 ... n-1 0-|||-::-|||-1 2 ... 0 0-|||- ... 0 0;;

,-|||-;-|||-(3) (x)_(1)+(n-1)(x)_(2)+... +2(x)_(n-1)+(x)_(n)=0

的值为 .-|||-n-1 0 ...0 0 0-|||-0 0 ...0 0 n-|||-A ((-1))^dfrac ((n-1)(n-2){2)n!}!-

12 lim_(n to infty) (1+2+3+...+(n-1))/(n^2);12 $\lim_{n \to \infty} \frac{1+2+3+

dfrac (1)(n-1)sum _(i=1)^n(({X)_(i)-overline (X))}^2 .-|||-n-|||-C. sqrt (dfrac

3.利用范德蒙德行列式计算下列行列式:-|||-a^n ((a-1))^n ((a-n))^n-|||-^n-1 ((a-1))^n-1 ((a-n))^n-1

(2n-1)(2n)(2n-2)... 2;-|||-(4) (n-1)... 1.

设x_(0)=0,x_(n)=(1+2x_(n-1))/(1+x_(n-1))(n=1,2,3,...),则lim_(ntoinfty)x_(n)=设$x_{0