+(n-1)ln dfrac (n-1)(n)] = ____

10.[单选题]-|||-10、高阶导数10-|||-((ln x))^(n)=-|||-A) ((-1))^n-1dfrac ((n-1)!)({x)^n-1

6.数列极限 lim _(narrow infty )n[ ln (n-1)-ln n] =

_(n)=dfrac (1)(2)((x)_(n-1)+dfrac ({a)^2}({x)_(n-1)}) n=1,2,···, 证明数列(xn)极限存在,并求

设有级数sum _ (n=1) ^ ( infty ) (-1)^ (n-1)n div (3^ {n-1)}.则该级数()A. 条件收敛B. 绝对收敛C.

的值为 .-|||-n-1 0 ...0 0 0-|||-0 0 ...0 0 n-|||-A ((-1))^dfrac ((n-1)(n-2){2)n!}!-

,-|||-;-|||-(3) (x)_(1)+(n-1)(x)_(2)+... +2(x)_(n-1)+(x)_(n)=0

判别级数 sum _(n=1)^infty dfrac (n)({3)^n-1} 的敛散性...

dfrac (1)(n-1)sum _(i=1)^n(({X)_(i)-overline (X))}^2 .-|||-n-|||-C. sqrt (dfrac

[单选题]y（n）+0.3y（n-1）=x（n）与y（n）=-0.2x（n）+x（n-1）是（）.

(6)收敛, lim _(narrow infty )dfrac ({2)^n-1}({3)^n}=0.-|||-(7) n-dfrac {1)(n)} 发