求$ \int\frac{cos2x}{cos^2xsin^2x} dx $。
求下列不定积分:-|||-(22) int dfrac (cos 2x)({cos )^2x(sin )^2x}dx ;
.int dfrac (1+{cos )^2x}(1+cos 2x)dx
int dfrac (cos 2x)(cos x+sin x)dx
int (e)^-2xsin dfrac (x)(2)dx; ;
)int dfrac (1)({cos )^2x(sin )^2x}dx.
(int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=( ) .(int )_(0)^dfrac (pi {4)}dfr
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((cos )^2x+dfrac (xcos x)(1+{cos )^2x})dx
int dfrac (sin x)(1+{cos )^2x}dx=-|||-__
( 20 int dfrac (dx)(1+cos 2x) ;
int dfrac (1)(1+cos 2x)dx=______.______.