37 int dfrac (dx)(xsqrt {{x)^2-1}}

(37 ) int dfrac (dx)(xsqrt {{x)^2-1}} ,

(37) int dfrac (dx)(xsqrt {{x)^2-1}}

int dfrac (dx)(xsqrt {{x)^2-1}}=____________________________

(9) int dfrac (1)(xsqrt {{x)^2-1}}dx

求(int )_(1)^+infty dfrac (dx)(xsqrt {2{x)^2-1}}=求

不定积分 int dfrac ({x)^2-1}(sqrt {xsqrt {x)}}dx=

求不定积分int dfrac (1)(xsqrt {{x)^2-1}}dx。求不定积分。

计算下列广义积分：(int )_(1)^+infty dfrac (dx)(xsqrt {2{x)^2-1}}计算下列广义积分：

计算下列定积分.-|||-(int )_(sqrt {2)}^2dfrac (dx)(xsqrt {{x)^2-1}} ;

)int dfrac (dx)(2{x)^2-1};