曲线=dfrac (x)(1-{x)^2}的渐近线是（ ）.=dfrac (x)(1-{x)^2}和=dfrac (x)(1-{x)^2}=dfrac (x)(1-{x)^2}和=dfrac (x)(1-{x)^2}=dfrac (x)(1-{x)^2}和=dfrac (x)(1-{x)^2}=dfrac (x)(1-{x)^2}和=dfrac (x)(1-{x)^2}

曲线=dfrac ({x)^dfrac (1{2)}}(1-{x)^2}（ ）曲线（）A.既有水平渐近线也有垂直渐近线B.仅有水平渐近线C.既无水平也无垂

=dfrac (x)(sqrt {1-{x)^2}}，则=dfrac (x)(sqrt {1-{x)^2}}=_________.，则=_________.

=dfrac (arcsin x)(x)+dfrac (1)(2)ln dfrac (1-sqrt {1-{x)^2}}(1+sqrt {1-{x)^2}}

设=dfrac (arcsin x)(sqrt {1-{x)^2}}（1）证明：=dfrac (arcsin x)(sqrt {1-{x)^2}}（2）求=df

lim _(xarrow 1)(dfrac (a)(1-{x)^2}+dfrac (x)(x-1))=dfrac (3)(2) = __

(6) () =dfrac (1)(sqrt {1-{x)^2}} int dfrac (1)(sqrt {1-{x)^2}}dx=() .

设=ln sqrt (dfrac {1-x)(1-{x)^2}}则 dy|=ln sqrt (dfrac {1-x)(1-{x)^2}}设则dy|

2.设曲线 =dfrac ({x)^2+x-2}(1-{x)^2} ,则该曲线的垂直渐近线为 __ .

8 单选 lim _(xarrow {0)^x}dfrac (1+{2)^dfrac (1{x)}}(1-{2)^dfrac (1{x)}}=

(4) =dfrac (x)(sqrt {1-{x)^2}}