(6) () '=dfrac (1)(sqrt {1-{x)^2}} int dfrac (1)(sqrt {1-{x)^2}}dx=() .

.int dfrac (sqrt {1+{x)^2}+sqrt (1-{x)^2}}(sqrt {1-{x)^4}}dx.

(6) int dfrac (dx)(1+sqrt {1-{x)^2}} ;

(1) int dfrac (dx)(1+sqrt {1-{x)^2}} ,

[题目] int dfrac (x)(sqrt {1-{x)^2}}dx

int dfrac (dx)(x+sqrt {1-{x)^2}}

int dfrac (dx)(x+sqrt {1-{x)^2}}..

(15) int dfrac ({x)^2}(sqrt {1-{x)^2}}dx

[题目]-|||-int (dfrac (3)(1+{x)^2}-dfrac (2)(sqrt {1-{x)^2}})dx

(25) int dfrac (1)(1+sqrt {1-{x)^2}}dx ;

求下列定积分:-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx