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int dfrac (dx)(x+sqrt {1-{x)^2}}
例24 int dfrac (dx)(x+sqrt {1-{x)^2}}
(int )_(-1)^1((x+sqrt {1-{x)^2})}^2dx=
求下列不定积分(其中a、b、w、φ均为常数):-|||-(41) int dfrac (dx)(1+sqrt {1-{x)^2}}-|||-(42) int d
(6) () =dfrac (1)(sqrt {1-{x)^2}} int dfrac (1)(sqrt {1-{x)^2}}dx=() .
[题目] int dfrac (x)(sqrt {1-{x)^2}}dx
求下列不定积分(其中a、b、b、φ均为常数):-|||-(41) int dfrac (dx)(1+sqrt {1-{x)^2}};-|||-(42) int
求下列不定积分(其中a、b、w、φ均为常数):-|||-(41) int dfrac (dx)(1+sqrt {1-{x)^2}};-|||-(42) int
.int dfrac (sqrt {1+{x)^2}+sqrt (1-{x)^2}}(sqrt {1-{x)^4}}dx.
(15) int dfrac ({x)^2}(sqrt {1-{x)^2}}dx