.int dfrac (sqrt {1+{x)^2}+sqrt (1-{x)^2}}(sqrt {1-{x)^4}}dx.

(6) () =dfrac (1)(sqrt {1-{x)^2}} int dfrac (1)(sqrt {1-{x)^2}}dx=() .

[题目]-|||-int (dfrac (3)(1+{x)^2}-dfrac (2)(sqrt {1-{x)^2}})dx

[题目] int dfrac (x)(sqrt {1-{x)^2}}dx

int dfrac (dx)(x+sqrt {1-{x)^2}}

int dfrac (dx)(x+sqrt {1-{x)^2}}..

(15) int dfrac ({x)^2}(sqrt {1-{x)^2}}dx

=dfrac (x)(sqrt {1-{x)^2}}，则=dfrac (x)(sqrt {1-{x)^2}}=_________.，则=_________.

(1) int dfrac (dx)(1+sqrt {1-{x)^2}} ,

计算定积分(int )_(0)^1dfrac (x)(x+1)sqrt (1-{x)^2}dx.计算定积分.

求下列定积分:-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx