设函数-|||-f(x)-|||-在区间-|||-(1,2)-|||-内连续,-|||-https:/img.zuoyebang.cc/zyb_dcce33fedbb879f2f73d0d083995cc16.jpglt (x)_(1)lt (x)_(2)lt (x)_(3)lt 2,-|||-证明:至少存在一点-|||-xi in (1,2)-|||-使得-|||-(xi )=dfrac (1)(3)[ f((x)_(1))+f((x)_(2))+f((x)_(3))]

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