例1 解"物不知数"问题中的同余方程组-|||- ) x=2(mod3) x=3(mod5) x=2(mod ) .

求同余式组{}x=2(mod3)x=2(mod4)x=1(mod5).的最小正整数解和所有正整数解.9. (20.0分) 求同余式组$\left\{\beg

方程组 _(1)-3(x)_(2)+(x)_(3)=2 有不同的向量解， _(1)-3(x)_(2)+(x)_(3)=2

解线性方程组: (x)_(1)+(x)_(2)-5(x)_(3)+(x)_(4)=8 (x)_(1)+(x)_(2)-5(x)_(3)+(x

解线性方程组_(1)-2(x)_(2)+(x)_(3)=-2-|||-__ __-|||-(x)_(1)+(x)_(2)-3(x)_(3)=1-|||--(x)

解方程组： ) (x)_(1)-(x)_(2)-(x)_(3)=2 2(x)_(1)-(x)_(2)-3(x)_(3)=1 3(x)_(1)+2(x)_(2)

[单选题]判断整型变量x是奇数的表达式是( )。A． x Mod 20B． x Mod 2 != 0C． x Mod 2 ≠ 0D． x Mod 2 = 0

2.解方程组 ) (x)_(1)+(x)_(2)+(x)_(3) (x)_(1)+(x)_(2)-(x)_(3)-(x)_(4)=1 5(x)_(1)+5(

解下列线性方程组 ) (x)_(1)+2(x)_(2)+3(x)_(3)=1 2(x)_(1)+2(x)_(2)+5(x)_(3)=2 3(x)_(1)+5(

5.线性方程组 ) (x)_(1)-(x)_(2)=(a)_(1) 2(x)_(2)-(x)_(3)=(a)_(2) (x)_(1)+(x)_(2)-(x)

例4 讨论线性方程组-|||- ) (x)_(1)+(x)_(2)+2(x)_(3)+3(x)_(4)=1 (x)_(1)+3(x)_(2)+6(x)_(3)