求极限 lim (sin sqrt (x+1)-sin sqrt (x)).

参考答案与解析：

相关试题

[题目] 求极限: lim _(xarrow -infty )dfrac (sqrt {4{x)^2+x-1}+x+1}(sqrt {{x)^2+sin x}}

[题目] 求极限: lim _(xarrow -infty )dfrac (sqrt {4{x)^2+x-1}+x+1}(sqrt {{x)^2+sin x}}

  • 查看答案

    • [例3]求极限 lim _(xarrow infty )dfrac (sqrt {4{x)^2+x-1}+x+1}(sqrt {{x)^2+sin x}}

    [例3]求极限 lim _(xarrow infty )dfrac (sqrt {4{x)^2+x-1}+x+1}(sqrt {{x)^2+sin x}}

  • 查看答案

    • 8.计算下列极限：(1) lim _(xarrow 0)dfrac (sin 4x)(sqrt {x+1)-1}(1) lim _(xarrow 0)dfrac (sin 4x)(sqrt {x+1)

    8.计算下列极限：(1) lim _(xarrow 0)dfrac (sin 4x)(sqrt {x+1)-1}(1) lim _(xarrow 0)dfrac

  • 查看答案

    • 求下列极限：lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}

    求下列极限：lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)

  • 查看答案

    • 求极限：lim _(xarrow 0)dfrac (3x)(1-sqrt {1+sin x)}

    求极限：lim _(xarrow 0)dfrac (3x)(1-sqrt {1+sin x)}求极限：

  • 查看答案

    • [题目]-|||-lim _(xarrow infty )dfrac (sqrt {4{x)^2+x-1}+x+1}(sqrt {{x)^2+sin x}}= ( )()

    [题目]-|||-lim _(xarrow infty )dfrac (sqrt {4{x)^2+x-1}+x+1}(sqrt {{x)^2+sin x}}=

  • 查看答案

    • 1、计算极限 lim _(xarrow 0)dfrac (sin x-tan x)({x)^2(sqrt (1+sin x)-1)}

    1、计算极限 lim _(xarrow 0)dfrac (sin x-tan x)({x)^2(sqrt (1+sin x)-1)}

  • 查看答案

    • [题目]求极限 lim _(xarrow 0)dfrac (sqrt {1+2sin x)-x-1}(xln (1+x))

    [题目]求极限 lim _(xarrow 0)dfrac (sqrt {1+2sin x)-x-1}(xln (1+x))

  • 查看答案

    • lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}= __

    lim _(xarrow 0)dfrac (sin x-tan x)((sqrt [3]{1+{x)^2}-1)(sqrt (1+sin x)-1)}= __

  • 查看答案

    • 求下列极限:-|||-(6) lim _(xarrow +infty )(x)^dfrac (3{2)}(sqrt (x+2)-2sqrt (x+1)+sqrt (x));

    求下列极限:-|||-(6) lim _(xarrow +infty )(x)^dfrac (3{2)}(sqrt (x+2)-2sqrt (x+1)+sqrt

  • 查看答案