设=dfrac (arcsin x)(sqrt {1-{x)^2}}(1)证明:=dfrac (arcsin x)(sqrt {1-{x)^2}}(2)求=df
例10]证明 (arcsin x)=dfrac (1)(sqrt {1-{x)^2}}
7.求下列函数的导数:-|||-(1) =arcsin (1-2x) ;-|||-(2) =dfrac (1)(sqrt {1-{x)^2}} ;-|||-(3
=dfrac (arcsin x)(x)+dfrac (1)(2)ln dfrac (1-sqrt {1-{x)^2}}(1+sqrt {1-{x)^2}}
(6) () =dfrac (1)(sqrt {1-{x)^2}} int dfrac (1)(sqrt {1-{x)^2}}dx=() .
函数 =arcsin sqrt (1-{x)^2}+dfrac (1)(sqrt {1-{x)^2}} 的定义域为 __ 。
=dfrac (x)(sqrt {1-{x)^2}},则=dfrac (x)(sqrt {1-{x)^2}}=_________.,则=_________.
、证明:当 -1lt xlt 0 时, arcsin sqrt (1-{x)^2}-arctan dfrac (x)(sqrt {1-{x)^2}}=dfrac
已知f(x)=(2x)/(sqrt (1-{x)^2)},则(df(sqrt (1-{x)^2)})/(dx)=(,,,,,)A、-2;B、-dfrac(2x)
8.求下列函数的导数:-|||-(10) =arcsin sqrt (dfrac {1-x)(1+x)}