【填空题】sin dfrac (11)(6)pi =___.

=-sqrt (2)(sin dfrac (pi )(6)+icos dfrac (pi )(6))的指数表达式为（ ）。A =-sqr

填空题-|||-lim _(xarrow 0)dfrac ({e)^x-(e)^-x}(sin x)= __

填空题.lim _(xarrow 0)dfrac (arcsin 2x)(sin 2x)=填空题.

[例2](1)(2020·全国卷Ⅲ)已知 sin theta +sin (theta +dfrac (pi )(3))=1,-|||-则 sin (theta

16、[填空题]-|||-5个3是 __ __ 个 dfrac (1)(6).

[题目]求函数 =2sin 3x, .in [ -dfrac (pi )(6),dfrac (pi )(6)] 的反函-|||-数.

+sin dfrac (pi )({2)^n}+... ;

+sin dfrac (npi )(2)+... （ ）A 、是收敛的 ; B 、是收敛的，其和为sin dfrac (pi )(2)+sin dfrac (2

(6) (int )_(0)^dfrac (pi {2)}(sin )^2xcos xdx;

( (int )_(dfrac {pi )(4)}^dfrac (pi {3)}dfrac (x)({sin )^2x}dx ;