填空题.lim _(xarrow 0)dfrac (arcsin 2x)(sin 2x)=

[题目] lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= __

求极限lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= ()求极限

[题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

[题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

0°.求下列极限.-|||-(4) lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

求lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac (1)({x)^2}).求.

(3) lim _(xarrow 0)dfrac (sin 2x)(sin 5x);

如图所示 7、 lim _(xarrow 0)dfrac (sin 2x)(x)= __ ,如图所示

lim _(xarrow 0)dfrac (ln ({sin )^2x+(e)^x)-x}(ln ({x)^2+(e)^2x)-2x}

求极限；（3）lim _(xarrow 0)dfrac (sin 2x)(sin 5x)；求极限；（3）；