如图所示 7、 lim _(xarrow 0)dfrac (sin 2x)(x)= __ ,

如图所示

参考答案与解析:

相关试题

[题目] lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= __

[题目] lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= __

  • 查看答案
  • (3) lim _(xarrow 0)dfrac (sin 2x)(sin 5x);

    (3) lim _(xarrow 0)dfrac (sin 2x)(sin 5x);

  • 查看答案
  • 求极限lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= ()

    求极限lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})= ()求极限

  • 查看答案
  • [题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

    [题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

  • 查看答案
  • [题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

    [题目]求 lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

  • 查看答案
  • 求lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac (1)({x)^2}).

    求lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac (1)({x)^2}).求.

  • 查看答案
  • 填空题.lim _(xarrow 0)dfrac (arcsin 2x)(sin 2x)=

    填空题.lim _(xarrow 0)dfrac (arcsin 2x)(sin 2x)=填空题.

  • 查看答案
  • 0°.求下列极限.-|||-(4) lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

    0°.求下列极限.-|||-(4) lim _(xarrow 0)(dfrac (1)({sin )^2x}-dfrac ({cos )^2x}({x)^2})

  • 查看答案
  • 求极限;(3)lim _(xarrow 0)dfrac (sin 2x)(sin 5x);

    求极限;(3)lim _(xarrow 0)dfrac (sin 2x)(sin 5x);求极限;(3);

  • 查看答案
  • 1.求下列极限:-|||-(1) lim _(xarrow 0)dfrac (sin 2x)(x);-|||-(3) lim _(xarrow dfrac {pi )(2)}dfrac (cos x)

    1.求下列极限:-|||-(1) lim _(xarrow 0)dfrac (sin 2x)(x);-|||-(3) lim _(xarrow dfrac {p

  • 查看答案